EXPRESSÃO ALGÉBRICA | VALOR NUMÉRICO DE UMA EXPRESSÃO ALGÉBRICA| Prof. Gis/

VALOR NUMÉRICO DE UMA EXPRESSÃO ALGÉBRICA ✓Nessa aula explico sobre COMO ENCONTRAR O VALOR …

EXPRESSÃO ALGÉBRICA | VALOR NUMÉRICO DE UMA EXPRESSÃO ALGÉBRICA| Prof. Gis//a>

Let’s remember how to calculate the numerical value of an algebraic expression? Who is confused and wants a tip from Gis? Let’s go? I’m going to start by asking you to subscribe to the channel if you’re not already subscribed and give a thumbs up for today’s class, because you ‘ll remember how to calculate the numerical value of an algebraic expression, oh Gis, but I want to learn what an expression algebraic. So I will leave an indication of the class that I explained in detail, what an algebraic expression is. And here we are going to solve just one exercise to calculate the numerical value, so mark it well, here today’s class is about the numerical value of the algebraic expression, I’ve already said a lot, right, so let’s go to class then guys. What is it, what is written here again, the numerical value, to emphasize well, folks, of the algebraic expression: 2x squared minus 3X – 5 / 2 when X = – 3. Guys, then the algebraic expression is given here and here is given the value of X for this algebraic expression. How am I going to do it now? What’s the strategy? The strategy is to take this algebraic expression and where we found the x, we’re going to exchange the X for the value that the statement gave us. For those of you who are confused, I have an algebraic expression but what value do I put for the variable, which is the letter, the value that the statement is giving you, in this case the statement gave minus three. But it’s likely that you’ll do another exercise where the statement puts eight here, or puts minus five, or puts 12. So it depends on the statement, so keep an eye on it, okay? So let’s start, I’m going to do it here twice because it’s twice because when I have 2x here between the letter and the number it’s a multiplication so it’s twice the X squared the X is minus three so Oh I’m going to put the X in red here and in parentheses and I have to square this X as it is here, then continuing minus three times, because here between the number the letter is times, three times the value of the I put red minus five all of this here then I’m going to divide by 2 ok so now let’s focus here on the numerator people, focus on the numerator. In the numerator I have multiplication and I have power and there is a subtraction, first we solve the power so here it will be, I will do it here in front, then it will be like this: two times negative 3 squared, negative 3 squared is what People are – 3 x – 3, 3 x3= 9 minus with minus plus so it’s going to be plus 9, so I’ll just go with 9 here. So this – 3 squared by 9 which is here will be multiplication 3 times 3= 9. Then as I have a multiplication I do the rule of signs o, minus and minus will be plus minus 5 all of this divided by 2, I followed the two. So let’s continue now I’m going to do a multiplication twice nine is 18, 18 plus 9 minus 5, all of this divided by 2, continuing now what will it look like now 18 plus nine is 27 and 27 – 5 is 22 and then I divide by two, how many number two is there 22 / 2 we are going to find the result of 11, so that means that the result, the numerical value, right people, the numerical value of this algebraic expression here when I change the X to minus three its numerical value it will be equal to 11. But if I replaced the X with another number, would the numerical value change? It would change people, that’s why I told you, I took an exercise in algebraic expression numerical value, right, algebraic expression. Look at the statement and highlight, just like I did here, what is the value of X and look at the algebraic expression where are you going to exchange the value of do, and you saw another important thing, you saw that to solve the numerator here I followed the rules of operations of numerical expressions. I didn’t solve it, first power, then I applied the sign rule, here I did the multiplication first. So I obeyed all the expression rules. Did you see how easy it is to do? If you liked this explanation, give Gis a thumbs up and subscribe to the channel and I’ll see you in the next class, bye…